Question

a train starting from rest attains a velocity of 45kmh-1 in 10secs. Calculate the acceleration

Answer 1

Hi..

Ur answer is 1.25ms^-2..


Hope this helps u!!

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Acceleration=1.25\:m/}s^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a train starting from rest attains a velocity of 45kmh-1 in 10secs.

• We have to find acceleration of train.

$\green{\underline\bold{Given :}} \\ :\implies \text{Initial\:velocity(u)=0 m/s} \\ \\ :\implies \text{Final \: velocity (v)= 45 \: km/h} \\ \\ :\implies \text{Time = 10 \: sec} \\ \\ \red{\underline \bold{To \: Find : }} \\ :\implies \text{Acceleration= ?}$

• According to given question :

$\text{Final \: velocity} = 45 \times \frac{5}{18} =12.5 \: ms \\ \\ \bold{Using \: first \: equation \: of \: motion : } \\ : \implies v = u + at \\ \\ : \implies 12.5 = 0 + a \times 10 \\ \\ : \implies 10 \times a = {12.5} \\ \\ : \implies a = \frac{12.5}{10} \\ \\ \green{ : \implies \text{a = 1.25 \: m}/{s}^{2} }$