Question

A train starting from rest attains a velocity of 52km/hr in 5 min. Assuming that acceleration is uniform. Find (i) acceleration (ii) the distance travelled by the train for attaining this velocity.

Answer 1

u=0 m/s

v=52 km/hr=20m/s

t=5min=5×60=300sec

a=v-u/t=20-0/300=1/15m/s^2

s=ut+1/2at^2

=0×300+1/2×1/15×300×300

=3000m

hope it is helpful...