A train starting from rest attains a velocity of 60km/hr in 20min. Assuming that acceleration is uniform. Find (i) acceleration (ii) the distance travelled by the train for attaining this velocity.
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- (1) .u= 0
- v= 60 km / h=60×5/18 = 16.67 m/s
- t= 20min =20×60 =1200 sec
- now v = u + at
- a= v-u /t
- a= 16.67-0/1200
- a = 0.0138 m /s²
- (2). as, s = ut +1/2 at²
- s= o+1/2×0.0138×1200×1200
- s= 9936 m
- s=
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