Question

a train starting from rest attains a velocity of 63 km/h in 5 mins assuming the acceleration in uniform find a) the acceleration b) the distance travelled by train for attaing this velocity.​

Answer 1

Answer:

Explanation:

Initial Velocity=u=0m/s

Final velocity= V= 72km/h

Time =5 min =5/60 h =1/12 h

acceleration=a=?

As we know that , a=v-u/t

⇒a=72-0/1/12

=72*12

=864km/h²

Distance travelled  =s=ut+1/2at²

=0x1/12 +1/2(864)(1/12)²

=(1/2)x864x(1/144)

=3km

∴Distance travelled by the train for attaining this velocity 3km.

Answer 2

Answer:

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