Question

a train starting from rest attains a velocity of 72 in 30 minutes.find its distance​

Answer 1

$\huge \bold {\red {\underline{\mathfrak{ANSWER}}}} \red{ :}$

$\star \: \: \: \blue{Given:}$

Initial Velocity= 0 m/s

Final Velocity= 72 m/s

Traveling Time= 30×60 sec

= 1800 s

$\star \: \: \: \blue{Solution : }$

${v }^{2} = {u}^{2} + 2aS \\ \longrightarrow \: {72}^{2} = {0}^{2} + 2 \times \frac{72 - 0}{30 \times 60} + S \\ \longrightarrow \: \boxed{S = 4896}$

$\bold {\bold{\boxed {\boxed{///MARK \: IT \: BRAINLIEST///}}}}$