Question

a train starting from rest attains a velocity of 72 in 30 minutes.find its distance​

Answer 1

Answer:

Explanation:

from an equation of motion s=ut+1/2at^2

time=30 minutes=(30)(60)=1800 seconds

v=72m/s

u=0( starts from rest)

a=(v-u/t)

s=(0)(1800)+1/2(v-u/t)(1800)(1800)

s=0+1/2 (72/1800)(1800)(1800)

s=1/2 (72) (1800)

s=(36) (72)

s=2592m