Question

A train starting from rest attains a velocity of 72 Km h-1

in 5

minutes. Assuming that the acceleration is uniform, find (a) the

acceleration and (b) the distance travelled by the train for

attaining this velocity.​

Answer 1

Answer:

...

acceleration = 4m/s² and

Distance travelled = 50m...

Explanation:

velocity= 72km/h...

In m/s = 72×1000/60×60= 20m/s

v= u+at

v 0+a×5

20= 5a

a= 20/5= 4

a= 4m/s²...

Now distance travelled

v² = u² + 2as

20×20 = 0² + 2× 4 × s

8s= 400

s = 400/8

s = 50m...

Answer 2

$\huge\mathcal\colorbox{purple}{{\color{red}{ᴀɴSᴡᴇƦ✧~~~}}}$

acceleration = 4m/s² and

Distance travelled = 50m...

velocity= 72km/h

In m/s = 72×1000/60×60= 20m/s

v= u+at

v 0+a×5

20= 5a

a= 20/5= 4

a= 4m/s²...

Now distance travelled

v² = u² + 2as

20×20 = 0² + 2× 4 × s

8s= 400

s = 400/8

s = 50m