Question

a train starting from rest attains a velocity of 72 km/h-1in 5 minutes. assuming that the acceleration is uniform,find (1)the acceleration (2) the distance travelled by the train and attaining the this velocity ​

Answer 1

Given:

Initial velocity (u) = 0

Final velocity (v) = 72 km/hr

Time taken (t) = 5 min = 1/12 hr

i) Acceleration:

We know that,

$\bullet$ $\boxed{\sf{Acceleration =\frac{(v - u)}{t}}}$

$\implies$ a = (72 - 0) / (1/12)

$\implies$ a = 72 / (1/12)

$\implies$ a = (72 × 12) / 1

$\implies$ a = 72 × 12

$\implies$ a = 864 km/hr²

Therefore, acceleration = 864 km/hr²

ii) The distance travelled by the train for attaining this velocity:

$\bullet$ $\boxed{\sf{s = ut + \frac{1}{2} at^{2} }}$

$\implies$ s = 0 × (1/12) + 1/2 × 864 × (1/12)²

$\implies$ s = 1 × 432 × (1/144)

$\implies$ s = 432 / 144

$\implies$ s = 3 km

Therefore, distance = 3 km

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Answered by: Niki Swar, Goa❤️

Answer 2

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