Question

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform. Find
(i) the acceleration.
(ii)the distance travelled by the train for attaining this velocity.​

Answer 1

Final velocity of train= 72*5/18 km/h= 20 km/h

Time = 5 mins= 300 s

(i) a= 20-0/300 m/s²= 1/15 m/s²= 0.066 m/s²

(ii) S= ut+1/2 at²= at²/2 (u=0)= 90000/450 m= 200 m

Answer 2

Here is the answer.............................