.A train starting from rest attains a velocity of 72 km h-'in 5 minutes. Assuming that the the acceleration is uniform, find the acceleration and distance travelled by the train for attaining this velocity.
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Answer:
Acceleration is 864m/s^2
Explanation:
s=ut+1/2at^2
s=0x5/60+1/2x864x(5/60)^2
s=3km
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