Question

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming the acceleration is uniform, find
(i) the acceleration.
(ii) the distance travelled.​

Answer 1

Explanation:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Answer 2

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