Question

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration
is uniform , find (i) the acceleration and (ii) the distance travelled by the train for attaining this
velocity.

Answer 1

v= 72kmph= 20m/s
u= 0
t= 5min= 300sec
a= v-u / t
= 20- 0/300
a= 0.06
s= ut + ½ at²
= ½ (0.06)(300)(300)
= 2700m