Question

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform , find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.

Answer 1

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Answer 2

U=0

v=72km/h=20m/s

t=5min=5×60=300sec

a=v-u/t

a=20-0/300

a=0.066m/s²

s=ut+1/2at²

s=0+1/2×0.066.(300²)

s=5940/2

s=2970m=2.97km

a=0.066m/s² and s=2.97km(Ans).