Question

a train starting from rest attains a velocity of 72 km/h in 5 min .Assuming that acceleration is unifrom find the acclerationa and distance

Answer 1

Answer:

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Answer 2

Complete step-by-step answer:

Given,

Initial velocity

=u=0m/s=u=0m/s

Final velocity=V=72km/h=V=72km/h

Time=5min=5min

We will convert minutes into hours.

=560h=112h=560h=112h

We have to find out acceleration:

We will denote acceleration by a and distance travelled by s.

Formula used:

a=v−ut⇒a=72−0112⇒a=72×12=864km/h2a=v−ut⇒a=72−0112⇒a=72×12=864km/h2

Hence the acceleration is 864km/h2864km/h2.

Now, the distance travelled by train:

Formula used:

s=ut+12at2=0×112+12(864)(112)2=12×864×1144=3kms=ut+12at2=0×112+12(864)(112)2=12×864×1144=3km

Hence, the distance travelled by train is 3km.