Question

A train starting from rest attains a velocity of 72 km/h in 5 minutes assuming that the acceleration is uniform find the distance travelled by tye train for attaining this velocity

Answer 1

Given :

Initial Velocity=u=0m/s

Final velocity= V= 72km/h

Time =5 min =5/60 h =1/12 h

acceleration=a=?

As we know that , a=v-u/t

⇒a=72-0/1/12

=72*12

=864km/h²

Distance travelled  = s = ut+1/2at²

=0 x 1/12 + 1/2(864)(1/12)²

=(1/2) x 864 x (1/144)

=3km

∴Distance travelled by the train for attaining this velocity 3km.

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Answer 2

Your answer is

Velocity=distance/time

Velocity= 72/ 5

Velocity= 14.4 ans..