A train starting from rest attains a velocity of 72 km/h in 5 min .Assuming the acceleration is uniform, find
1. the acceleration
2.the distance travelled by the train for attaining his velocity
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given-
u = 0
v = 20 m/s
t = 60 * 5 = 300 s
now,
a = v - u / t
a = (20 - 0 ) m/s ÷ 300 s
a = 20 ÷300
= 0.06 m/ s^2
then,
s = ut + 1/2 at^2
= 0 * 300 + 1/2 * 0.06 * 300*300
= 0 + 0.03 * 300 *300
= 9 *300 m
= 2700 m
u = 0
v = 20 m/s
t = 60 * 5 = 300 s
now,
a = v - u / t
a = (20 - 0 ) m/s ÷ 300 s
a = 20 ÷300
= 0.06 m/ s^2
then,
s = ut + 1/2 at^2
= 0 * 300 + 1/2 * 0.06 * 300*300
= 0 + 0.03 * 300 *300
= 9 *300 m
= 2700 m
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