Question

A train starting from rest attains a velocity of 72 km/h in 5 minutes find the acceleration and distance travelled

Answer 1

u=0(as it starts from rest)

v=72×5/18

=20m/sec

t=5min=5×60=300sec

v=u+at

20=a×300

a=20÷300

=1/15 m/s^2

S=ut+1/2 at^2

=675000m