A train starting from rest attains a velocity of 72 km per hour in 5 minutes find the acceleration
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Answer:
v=displacement÷time. so,v=72=displacement÷time 0.0833.so, displacement=v×t=72×0.0833= 5.96.
. so, acceleration=distance÷time. then,a=72÷5.96=12.08 (approx)=12m/s
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