A train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming that acceleration is uniform find the distance travelled by the train for attending this velocity
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Answered by
13
Heya, find the answer in the attached image.
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Thanks.
Hope this helps. . . . . if it really helped, then please mark it as the BRAINLIEST and please say a thanks.
Thanks.
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BackbencherAshu:
Excuse me, I belief the answer you wrote has an error!
Hey there,m sorry but I think that it is correct.
Sorry, my bad!
Wrong comment over a place!
It is okay.
Hmm.....
Answered by
4
As per question,
u = 0 m/s
v= 72kmph
= 72 * 5÷18 m/s
= 20 m/s
t= 5 min
= 300 sec
distance (s)=?
As given, acceleration is uniform
V = u/2+v/2
= 0/2+ 20÷2
= 10 m/s
s=vt
= 10 * 300
= 3000 m = 3 km
so, s = 3 km
u = 0 m/s
v= 72kmph
= 72 * 5÷18 m/s
= 20 m/s
t= 5 min
= 300 sec
distance (s)=?
As given, acceleration is uniform
V = u/2+v/2
= 0/2+ 20÷2
= 10 m/s
s=vt
= 10 * 300
= 3000 m = 3 km
so, s = 3 km
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