Question

a train starting from rest attains a velocity of 72 km per hour in 5 minute as human the acceleration is uniform find
1) the acceleration
2) the distance travelled by the train for attaining this velocity ​

Answer 1

Answer:

hope it helps you

Explanation:

thanks

Answer 2

Given :

• Initial Velocity = 0 m/s
• Final Velocity = 72 km/hr
• Time Taken = 5 min.

To Find :

• Acceleration and Distance travelled by the train .

Solution :

$\longmapsto\tt{Final\:Velocity(v)=70km/h=20m/s}$

$\longmapsto\tt{Time\:Taken(t)=5\:min=300\:sec}$

Using 1st Equation :

$\longmapsto\tt\boxed{v=u+at}$

Putting Values :

$\longmapsto\tt{20=0+a\times{300}}$

$\longmapsto\tt{20=0+300a}$

$\longmapsto\tt{20=300a}$

$\longmapsto\tt{a=\cancel\dfrac{20}{300}}$

$\longmapsto\tt\bf{a=0.06{m/s}^{2}}$

So , The Acceleration is 0.06 m/s² ...

Now ,

For Distance :

Using 2nd Equation :

$\longmapsto\tt\boxed{s=ut+\dfrac{1}{2}{at}^{2}}$

Putting Values :

$\longmapsto\tt{0\times{300}+\dfrac{1}{{\cancel{2}}}\times{0.06}\times{{\cancel{300}}}\times{300}}$

$\longmapsto\tt{0.06\times{150}\times{300}}$

$\longmapsto\tt\bf{2700\:m}$

So , The Distance Travelled is 2700 m...