Question

a train starting from rest attains a velocity of 72 km per hour in a 5 minute assume that the acceleration in uniform find. 1) the acceleration of the train . 2) the distance travelled by the train from attend the velocity

Answer 1

heya hope this helps

Answer 2

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Here is ur answer :--

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Given,

Initial velocity, u = 0

Final velocity, v = 72 km/ h

= 72000/3600 m/s

= 20m/s

Time, t = 5 minutes

= 5* 60

= 300seconds

1) Acceleration, a = v - u / t

a = 20 - 0 / 300

= 20/300

= 0.06m/s^2

2) 2as = v^2 - u^2

=> 2 * 0.06 * s = 20^2 - 0^2

=> 33.33 s = 400

=> s = 400/ 33.33

=> s = 12m

Therefore, distance travelled is 12m

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Hope it helps!!