Question

a train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming that acceleration is uniform find acceleration distance travelled by train

Answer 1

u (initial velocity) = 0 m/s
v=72 km/h
t= 5 mins =0.0833 hrs

a= v-u/t
=> a=72-0/0.0833
=> a= 72/0.0833
=> a= 864. 34 m/s^2