Question

A train starting from rest attains a velocity of 72 km per hour in 5 minutes. Assuming the acceleration is uniform find [i] acceleration [ii] the distance travelled by the train for attaining this velocity *

Answer 1

Answer:

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Explanation:

intial velocity u = 0 km/h

final velocity v = 72 km/h

time t = 5 min = 5/60 h = 1/12 h

acceleration a = v-u / t = 72 - 0 / 1 / 12

= 72 ×12 = 864 km/ h²

distance s = ut + 1/2 at²

= 0× 1/12 + 1/2 × 864 × (1/12)²

= 0 + 1/2 × 864 × 1/144

= 3 km