a train starting from rest attains a velocity of 72 km per hour in 5 minutes . assuming that the acceleration is uniform find the acceleration and the distance travelled by the train for attaining this velocity class 9 chapter motion
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u=0m/s
v=72km/h 72*1000m/3600s=20m/s
t=5min =300s
a=? s=?
v=u+at
20=0+a.300
a=1/15m/s^2
s=ut+1/2at^2
s=0*300+1/2*1/15*900
s=30 m
v=72km/h 72*1000m/3600s=20m/s
t=5min =300s
a=? s=?
v=u+at
20=0+a.300
a=1/15m/s^2
s=ut+1/2at^2
s=0*300+1/2*1/15*900
s=30 m
tell me briefly about last two steps
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