Question

a train starting from rest attains a velocity of 72 km per hour in 5 minutes .
assuming the acceleration is uniform find the acceleration and the distance travelled

Answer 1

u = 0 m/s
v = 72 kmph = 72 * 1000/3600 = 20 m/s
t = 5min = 5*60 = 300s
a = (v-u)/t = (20-0)/300 = 20/300 = 20.066 mps^2
s = ut + 1/2(a)(t)(t)
= (0)(300) + (1/2)(20.066)(300)(300)
= 0 + (20.066)(150)(300)
= 902970 meteres or 902.97 km.............

Answer 2

Hope this will help you....
While solving in exam solve step by step. ........