Question

A train starting from rest attains a velocity of 72 km per hour in 5 minutes assume that that the acceleration is uniform find (A) the acceleration (b)distance travelled by the train for attending this velocity

Answer 1

let see what is the answer

Answer 2

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U=0m/s

V=72km/hr=20m/s

T=5minutes=300seconds

by applying formula,

V=U+AT

=>20=0+300A

=>300A=20

=>A=20/300

=>A=1/15m/s²

Now, we use

V²=U²+2AS

20²=0²+2(1/15)S

400=2S/15

S=(400*15)/2

 =200*15

 =3000m

 =3km