Question

A train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming that the acceleration is uniform find the acceleration and the distance travelled by the train for attaining this velocity​

Answer 1

u= 0m/s

v= 72km/h= 20m/s

t= 5min=300s

a=v-u/t

= 72-0/300 =1/15m/s2

1/15m/s2= 0.06666666666 m/s2

2as=v2-u2

s=v2-u2/2a

=20 x 20/2  x (1/15)

=3000m

3km