Question

A train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming that the acceleration is uniform find the acceleration distance travelled by the train for attaining the spelling city

Answer 1

$here's \: your \: answer$

u=0 m/s

$velocity =$
=72 km/h =20m/s

$time \: taken$

=5 min =300s

$acceleration$


=$\frac{v - u}{t}$

=(20-0)/300

=20/300

=1/15 m/s2

s =ut+1/2 at2

=0+1/2×1/15×300×300

=1/30×300×300

=3000 m

=3 km

$thanks$

Answer 2

Question:
A train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming that the acceleration is uniform find the acceleration & distance travelled by the train for attaining the spelling city.

Answer:

$Acceleration = \frac{1}{15} m/ {s}^{2} \: \\ Distance \: travelled \: by \: train =3 \: km \:$

Step by step explanation:

According to the given question,

Initial velocity(u) = 0 km/h = 0 m/s

Final velocity(v) = 72 km/h = 72 × 5/18

= 20 m/s

Time taken(t) = 5 min = 5 × 60 sec

= 300 sec

FORMULA TO BE USED TO FIND ACCELERATION:

$v = u + at$

Put the value in the formula:

=> 20 = 0 + 300a

=> a = 20/300

=> a = 1/15 m/s²

So,

$Acceleration = \frac{1}{15} m/ {s}^{2}$

FORMULA TO BE USED TO FIND DISTANCE TRAVELLED BY THE TRAIN:

$s = ut + \frac{1}{2} a {t}^{2}$

Put the value in the formula:

=> s = 0 + 1/2×1/15×(300)²

=> s = 1/30×90000

=> s = 3000 m

=> s = 3 km

So,

$Distance \: travelled \: by \: train =3 \: km$