Question

a train starting from rest attains a velocity of 72 km per hour in 5 minutes assuming the acceleration is uniform find the acceleration and the distance travelled by the train​

Answer 1

Answer:

a = 0.066 m/s²

s = 3000 m

Explanation:

72 km/h = 72 x 5 / 18 = 20 m/s

5 min = 5 x 60 = 300 sec

u = 0 m/s

v = 20 m/s

t = 300 s

a = (v - u) / t

  = (20 - 0) / 300

  = 1 / 15

a = 0.066 m/s²

s = ut + 1/2at²

  = 0(300) + (1 / 2 x 1 / 15 x 300²)

  = 0 + 3000

s = 3000 m

Hope this helps! :)