Question

A train starting from rest attains a velocity of 72 kmh-1 in 5 minute assuming that the acceleration is unuform find the acceleration and distance travelled by the train for attaining this velocity

Answer 1

v=u+at

72*1000/3600=o+a*5*60

20=300a
a=20/300
a=1/15m/sec^2


s=ut+1/2at^2
s=1/2*1/15*300*300

s=1/30*300*300
s=1000m

1km

Answer 2

plzz refer the attachment

HOPE IT HELPS