Question

). A train starting from rest attains a velocity of 72 kmh-in 5 minutes. Assuming that the
acceleration is uniform, find (1) the acceleration, and (ii) the distance travelled by the
train for attaining this velocity.
[Ans.(i) --ms-, (ii)3.0 km
15​

Answer 1

So here's your answer mate..

U=0 m/sec

V=72km/sec

72*5/18 =20m/ sec

Time=5*60=300 sec

From first equation of motion

V=u+at

20=0+a*300

20/300 =a

A = 1/15 = 0.06m/s^2

From second equation of motion

2as=vsquare - u square

2*1/15 *s = 20* 20 -0

S= 15*20*10 =3000m

S = 3 km

Hope i helped you