Question

a train starting from rest attains a velocity of 72km/hr in 5 minute. Assuming that the acceleration is uniform find
1. The accelaration
2. The distance travelled by the train for attaining this velocity

Answer 1

1. The units have to be in standard form.

72 km = 72000m

5 min = 60×5 = 300 sec

Acceleration = Change in velocity/ Time

= 72000/300

= 240 m/s^2

2. Velocity = Distance(with direction)/Time

V = d/t

72000 = d/300

72000 × 300 = d

d = 21600000m

d = 21600km