Question

a train starting from rest attains a velocity of 74 km/h in 5 min. assuming the acceleration is uniform.find
1.the acceleration
2.the distance travelled by the train for attaining this velocity

Answer 1

Answer:

1. a = 0.0685 m/s^2

2. s = 3082.5 m

Explanation:

1. Here, v=20.55 m/s

             u=0 m/s

             t=300 s

By applying the first equation of motion: v=u+at

20.55 = 0 + 300a

20.55 = 300a

20.55/300 = a

a = 0.0685 m/s^2

2. Here, v=20.55 m/s

              u=0 m/s

              t=300 s

              a= 0.0685 m/s^2

By applying the second equation of motion: s = ut + ½ at^2

s = 0 x 300 + 1/2 x 0.0685 x 300^2

s = 3082.5 m