Question

 A train starting from rest attains a velocity of 89 kilometre per hour in 5 minutes. find the acceleration in mere per second​

Answer 1

Answer:

3km

Explanation:

We have to find out acceleration: We will denote acceleration by a and distance travelled by s. Hence the acceleration is 864km/h2. Hence, the distance travelled by train is 3km.

Answer 2

Answer:

Given,

Initial velocity=u=0m/s

Final velocity=V=72km/h

Time=5min

We will convert minutes into hours.

=560h=112h

We have to find out acceleration:

We will denote acceleration by a and distance travelled by s.

Formula used:

a=v−ut⇒a=72−0112⇒a=72×12=864km/h2

Hence the acceleration is 864km/h2.

Now, the distance travelled by train:

Formula used:

s=ut+12at2=0×112+12(864)(112)2=12×864×1144=3km

Hence, the distance travelled by train is 3km.

Note: Basic knowledge of laws of motion is very important, Also remember the fact the distance and displacement are two different things. Whenever the acceleration is slowing the initial speed that is acceleration is in the opposite direction of the velocity it is called deceleration.