Question

A train starting from rest attains a velocity of 90 km/h in 2 minutes. Assuming the acceleration to be uniform, find the value of a) acceleration b) distance travelled in 2 minutes

Answer 1

Answer:

I am not sure about the answer

Answer 2

Explanation with answer:

u = 0 km/h

v = 90 km /h

t = 2 min =  $\frac{2}{60}=\frac{1}{30}$ h

a)  acceleration = $\frac{v-u}{t}$

a = 90 - 0 /  $\frac{1}{30}$

= 90 * 30

= 2700 km/ h^2

b) 2as = v^2 - u^2

2 * 2700 *s = 90^2 - 0^2

2* 2700 *s = 8100

s= 8100 / 2700 *2

= 81/ 54

= 9/6

= 3/2 km

hope this helps

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