Question

a train starting from rest attains a velocity of 90 km per hour in 20 minutes if it is assume that acceleration is uniform find acceleration and distance travelled by the train​

Answer 1

according to my logic:-

s=d/t

and to find d

so, d=s x t

s=90km/h = 25m/s

t=20min = 1200 s

so the distance travelled is:-

25x1200=  30000m

30,000m is equal to 30 km

so the distance travelled is 30km

hope that helped...

plzzz mark as brainliest

Answer 2

V=90km/h =25m/s

U=0 km/h (starting from rest)

T=20 min =20*60 sec

a=V-U/T (1st law of newton)

=25-0/20*60 m/sec(sq.)

S=V2(square)-U2(square)/2a (Newton 3rd law)

=(25)2(square) - (0)2(square) /2*25

=15000 meters

=15 kms