A train starting from rest attains a velocity of 90km/h in 2 mins the the distance travelled by the train for attending this velocity is what
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Answer:
3km
Step-by-step explanation:
acceleration =(v-u)/t
=(25-0)/120
=5/12 m/s^2
distance=ut+1/2at^2
=(0×120)+(1/2×5/12×120×120)
=0+3000
=3000m
=3 km
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