A train starting from rest attains the velocity beyond of 72km/h. If the train has taken 5 minutes it would have travelled a distance of (A)15km (B) 3km (c) 6km (d) none of these
Answers
Answered by
1
5 min means 300 sec
v=72km/h means 20 m/s
u=0
a= v–u/t=20/300=1/15 m/s sqr
s=ut +0.5 at sqr
s=0+0.5*1/15*300*300
s=3000m=3 km
option B is correct
v=72km/h means 20 m/s
u=0
a= v–u/t=20/300=1/15 m/s sqr
s=ut +0.5 at sqr
s=0+0.5*1/15*300*300
s=3000m=3 km
option B is correct
Dishantmeena205:
Yarrrrr ache se samja
kya smjme nai aya vo bata
v-u= at se tuje acceleration mil jayega
u zero hoga bcz it start from rest
then s= ut +half at ^2
valur rkde mil jayega
ok bhai thnx
Similar questions