A train starting from rest attains velocity of 72km/h in 5min assuming that acceleration is uniform find
1)Acceleration
2)the distance travelled by the train for attaining this velocity
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Given :
Initial Velocity=u=0m/s
Final velocity= V= 72km/h
Time =5 min =5/60 h =1/12 h
acceleration=a=?
As we know that , a=v-u/t
⇒a=72-0/1/12
=72*12
=864km/h²
Distance travelled =s=ut+1/2at²
=0x1/12 +1/2(864)(1/12)²
=(1/2)x864x(1/144)
=3km
∴Distance travelled by the train for attaining this velocity 3km.
THANKS!!
Initial Velocity=u=0m/s
Final velocity= V= 72km/h
Time =5 min =5/60 h =1/12 h
acceleration=a=?
As we know that , a=v-u/t
⇒a=72-0/1/12
=72*12
=864km/h²
Distance travelled =s=ut+1/2at²
=0x1/12 +1/2(864)(1/12)²
=(1/2)x864x(1/144)
=3km
∴Distance travelled by the train for attaining this velocity 3km.
THANKS!!
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