a train starting from rest attains velocity of 72km/hr in 5 min. assuming that the acceleration uniform find the acceleration during this time
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Answered by
1
acceleration = 14.4 ...
utkarshanand60:
with whole solution
we have to divide 72 by 5. then we will get answer in decimal.
oky thankuu
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Answered by
7
your ans
as the train is starting from rest so
u=0
v=72km/h-----m/sec
72×5/18=20m/sec
v=20
t=5min------sec
1min=60sec
5×60=120sec
time=120
a=v-u/t
a=20-0/120
a=20/120
a=0.16m/sec2
as the train is starting from rest so
u=0
v=72km/h-----m/sec
72×5/18=20m/sec
v=20
t=5min------sec
1min=60sec
5×60=120sec
time=120
a=v-u/t
a=20-0/120
a=20/120
a=0.16m/sec2
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