A train starting from rest covers a distance of 150m in 58. Find Find the values of Initial velocity, u Displacement, s Time, t ws Acceleration, a Velocity after 5s, v Assuming that the velocity is constant after 5s, the time taken to cover 270m (from beginning)
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Given,
a=10m/s
2
u=0m/s
t=5sec
From 2nd equation of motion,
S=ut+
2
1
at
2
S=0×5+
2
1
×10×5×5
S=0+125
S=125m
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Answer:
Distance =125m
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