Question

A train starting from rest in a railway station acquires a velocity of 18Kmh-1 in 3s. Find (i) the acceleration and (ii) distance covered by the train.​

Answer 1

Explanation:

u = 0

v = 18kmph

t = 3s

18 kmph = 18 × 5 / 18 = 5 m/s

a = v - u / t

= 5 -0 / 3

= 5 / 3 m/s^2

d = ut + 1/2 at^2

= 0 + 1/2 × 5/3 × 3^2

= 1/2 × 5/3 × 9

= 1/2 × 15

= 7.5 or 7 1/2 metre

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