a train starting from rest moved with a uniform acceleration of 0.2m per sec square for five min. calc the speed acquired and dist trav in this time
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s= ut +1/2 at^2
s=90 m. s means here distance
speed=distance/time
= 90/300
=0.3 m/sec
s=90 m. s means here distance
speed=distance/time
= 90/300
=0.3 m/sec
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