Question

A train starting from rest moves with a uniform acceleration of 0.2 m/s for 5 minutes. Calculate the speed acquired and distance travelled in this time.

Answer 1

U =0
A =0.2m/s
T =5min = 5×60 = 300s
S =?
Speed =?
S =ut + 1÷2at×t
=o + 1÷2×0.2×300×300
=0+9000
= 9000
S=9000m
Distance = speed ×time
9000 = speed×300
9000÷300 = speed
30 =speed
Speed =30m/s

Answer 2

• Initial speed = 0

• time taken = 5 min = 300 s

• let final speed = v

then,

Use kinematics equation ,

$:\implies$ v = u + at

= 0 + 0.2 × 300 = 60 m/s

and distance travelled = S ( let )

Use formula ,

S = ut + 1/2at²

= 0 + 1/2 × 0.2 × (300)²

= 0.1 × 90000

= 9000 m

= 9 km