Question

a train starting from rest moves with a uniform acceleration of 2.1 square 5 minutes.calculate the speed acquired and distance travelled in this time ​

Answer 1

Answer:

Initial speed = 0

time taken = 5 min = 300 s

let final speed = v

then,

use kinematics equation ,

v = u + at

= 0 + 0.2 × 300 = 60 m/s

and distance travelled = S ( let )

use formula ,

S = ut + 1/2at²

= 0 + 1/2 × 0.2 × (300)²

=0.1 × 90000

=9000 m

= 9 km

Answer 2

Initial speed = 0

time taken = 5 min = 300 s

let final speed = v

then,

use kinematics equation ,

v = u + at

= 0 + 0.2 × 300 = 60 m/s

and distance travelled = S ( let )

use formula ,

S = ut + 1/2at²

= 0 + 1/2 × 0.2 × (300)²

=0.1 × 90000

=9000 m

= 9 km