Question

A train starting from rest moves with a uniform acceleration of 0.2metre per square second for 5 minutes. Calculate the final velocity and the distance travelled in this time.

Answer 1

Answer:

9 km

Explanation:

initial speed = 0

time take = 5min = 300s

let final speed = V

then, use kinematics equation

V = U+ at

= 0+ 0.2 * 300= 60 m/s

and distance travelled = S( let )

use formula

S= ut + 1/2 at 2

0+1/2* 0=2* (300)2

0.1* 90000

9000m

9 km

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