Physics, asked by nyashabharti27, 1 year ago

A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.

Answers

Answered by Anonymous
13
hello friend...!!!

according t the given question.

a ( acceleration ) = 0.2 m/s² 

u ( inital velocity ) = 0 m/s

v ( final velocity ) = ????

t ( time ) = 5 min = 300 seconds

we know that ,

V = u + at ----------( 1)

implies,

v = 0 +  0.2 ( 300 )

v =  60 m / s is the speed

now, to calculate the distance , 

we know s = ut + 1/2 at²

therefore ,

s = (0)t + 1/2 ( 0.2) ( 300)²

s = 9000 m = 9 Km.

therefore the speed acquired is 60 m/s and the distance covered is 9Km.

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hope it helps...!!

rajputdevansh15: really thanks
Answered by Anonymous
0

1234567890000 Explanation:

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