A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.
Answers
Answered by
13
hello friend...!!!
according t the given question.
a ( acceleration ) = 0.2 m/s²
u ( inital velocity ) = 0 m/s
v ( final velocity ) = ????
t ( time ) = 5 min = 300 seconds
we know that ,
V = u + at ----------( 1)
implies,
v = 0 + 0.2 ( 300 )
v = 60 m / s is the speed
now, to calculate the distance ,
we know s = ut + 1/2 at²
therefore ,
s = (0)t + 1/2 ( 0.2) ( 300)²
s = 9000 m = 9 Km.
therefore the speed acquired is 60 m/s and the distance covered is 9Km.
-----------------------------------------------------
hope it helps...!!
according t the given question.
a ( acceleration ) = 0.2 m/s²
u ( inital velocity ) = 0 m/s
v ( final velocity ) = ????
t ( time ) = 5 min = 300 seconds
we know that ,
V = u + at ----------( 1)
implies,
v = 0 + 0.2 ( 300 )
v = 60 m / s is the speed
now, to calculate the distance ,
we know s = ut + 1/2 at²
therefore ,
s = (0)t + 1/2 ( 0.2) ( 300)²
s = 9000 m = 9 Km.
therefore the speed acquired is 60 m/s and the distance covered is 9Km.
-----------------------------------------------------
hope it helps...!!
rajputdevansh15:
really thanks
Answered by
0
1234567890000 Explanation:
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