Question

A train starting from rest moves with a uniform acceleration of 0.2 m/ s for 5 min calculate the speed acquire and the distance travel in this time

Answer 1

u =0
a= 0.2m/s^
t=5min = 5*60 =300sec
s=?

s= ut+1/2at^
= 0*300+1/2*0.2*300^
=0+0.1*90000
=9000. (answer)

Answer 2

Given:

• u = 0
• a = 0.2 m/s²
• t = 5 min = 5 x 60 s = 300 s

To find

• v = ?
• s =?

Solution :

v = u + at

v = 0 + 0.2 x 300 = 60 m/s²

v² - u² = 2 as

s = (v² - u ²)/ 2a

s = (60² - 0²)/ 2 x 0.2

s = 9000 m

s = 9 km

=> 60 m/s² the speed acquire and the 9 km distance travel in this time