Question

A train starting from rest moves with a uniform acceleration of 0.2m/s^2for 5 minutes. Calculate the speed acquired and the distance travelled in this time.​

Answer 1

Answer:

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Answer 2

Answer:

Initial velocity, u=0m/s

Final velocity, yv=?

Acceleration, a=0.2m/s

2

Time, t=5min=5×60=300sec

Using first equation of motion to obtain the final speed:

v=u+at

v=0+0.2×300=60m/s

And the distance travelled is

s=ut+

2

1

αt

2

s=0×300+

2

1

×0.2×300×300

s=0+9000=9000m=9km