Question

A train starting from rest moves with a uniform acceleration of 0.1 ms-2 for 2 minutes. Find the speed acquired and the distance travelled.​

Answer 1

Explanation:

(a) Acceleration

The train starts from rest.

Therefore, initial velocity (u) = 0 m/s

Acceleration (a) = 0.1 m.s-²

Time = 2 minutes = 120 s

Acceleration is given by the equation a=(v-u)/t

Therefore, terminal velocity (v) = (at)+u

= (0.1 m.s-² * 120s) + 0 m.s-1

= 12m.s-¹ + 0 m.s-¹

Therefore, terminal velocity (v) = 12m/s

(b) As per the third motion equation,

Since a = 0.1 m.s-², v = 12 m.s-¹, u = 0 m.s-¹, and t = 120s, the following value for s (distance) can be obtained.

Distance, s =(v² – u²)/2a

=(12² – 0²)/2(0.1)

Therefore, s = 720m.

The speed acquired is 12m.s-¹ and the total distance traveled is 720m.

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Answer 2

Given:-  

• The bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes

To Find:-  

• Acceleration and distance travelled

Solution:-

(a) Acceleration

The bus starts from rest.

∴ Initial velocity (u) = 0 m/s  

Acceleration (a) = 0.1 m.s⁻²

Time = 2 minutes = 120 s

Acceleration is given by the equation a = ( v - u ) / t  

∴ Terminal velocity (v) = (at)+u

= (0.1 m.s⁻² × 120s) + 0 m.s⁻¹

= 12m.s⁻¹ + 0 m.s⁻¹

Therefore, terminal velocity (v) = 12m/s

______________________________________________

(b) As per the third motion equation,

Since a = 0.1 m.s⁻², v = 12 m.s⁻¹, u = 0 m.s⁻¹, and t = 120s, the following value for s (distance) can be obtained.

Distance, s = (v² – u²) / 2a

= (12² – 0²) / 2 (0.1)

Therefore, s = 720m.

∴ The speed acquired is 12m.s⁻¹ and the total distance traveled is 720m.

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